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The product $2^{1/4} \cdot 4^{1/16} \cdot 8^{1/48} \cdot 16^{1/128} \ldots$ to $\infty$ is equal to:
(1) $2^{1/2}$
(2) $2^{1/4}$
(3) 1
(4) $2$
$= 2^{1/4} \cdot 2^{2/16} \cdot 2^{3/48} \cdot \ldots = 2^{1/4 + 1/8 + 1/16 + \ldots} = 2^{1/2} = \sqrt{2}$
BETA
