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JEE PYQ: Sets And Relations Question 4

Question 4 - 2021 (26 Feb Shift 1)

Let $R = {(P, Q) \mid P \text{ and } Q \text{ are at the same distance from the origin}}$ be a relation, then the equivalence class of $(1, -1)$ is the set:

(1) $S = {(x, y) \mid x^2 + y^2 = 1}$

(2) $S = {(x, y) \mid x^2 + y^2 = 4}$

(3) $S = {(x, y) \mid x^2 + y^2 = \sqrt{2}}$

(4) $S = {(x, y) \mid x^2 + y^2 = 2}$

Show Answer

Answer: (4)

Solution

$P(a, b), Q(c, d), PO = QO$

$\Rightarrow a^2 + b^2 = c^2 + d^2$

$R(x, y), \quad s = (1, -1) \Rightarrow RO = SO$

($\because$ equivalence class)

$x^2 + y^2 = 2$


Learning Progress: Step 4 of 16 in this series