JEE PYQ: Statistics Question 24
Question 24 - 2019 (08 Apr Shift 2)
A student scores the following marks in five tests: 45, 54, 41, 57, 43. His score is not known for the sixth test. If the mean score is 48 in the six tests, then the standard deviation of the marks in six tests is:
(1) $\frac{10}{\sqrt{3}}$ (2) $\frac{100}{3}$ (3) $\frac{10}{3}$ (4) $\frac{100}{\sqrt{3}}$
Show Answer
Answer: (1) $\frac{10}{\sqrt{3}}$
Solution
Sixth score $= 48$. $\sigma = \sqrt{\frac{200}{6}} = \frac{10}{\sqrt{3}}$.
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