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If the standard deviation of the numbers $-1, 0, 1, k$ is $\sqrt{5}$ where $k > 0$, then $k$ is equal to:
(1) $2\sqrt{6}$ (2) $2\sqrt{\frac{10}{3}}$ (3) $4\sqrt{\frac{5}{3}}$ (4) $\sqrt{6}$
$3k^2 + 8 = 80$, $k^2 = 24$, $k = 2\sqrt{6}$.
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