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If mean and standard deviation of 5 observations $x_1, x_2, x_3, x_4, x_5$ are 10 and 3, respectively, then the variance of 6 observations $x_1, x_2, \ldots, x_5$ and $-50$ is equal to:
(1) 509.5 (2) 586.5 (3) 582.5 (4) 507.5
$\sum x_i^2 = 545$. Variance of 6 observations $= \frac{3045}{6} = 507.5$.
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