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Let $A(3, 0, -1)$, $B(2, 10, 6)$ and $C(1, 2, 1)$ be the vertices of a triangle and $M$ be the midpoint of $AC$. If $G$ divides $BM$ in the ratio, $2 : 1$, then $\cos(\angle GOA)$ ($O$ being the origin) is equal to:
(1) $\frac{1}{2\sqrt{15}}$
(2) $\frac{1}{\sqrt{15}}$
(3) $\frac{1}{6\sqrt{10}}$
(4) $\frac{1}{\sqrt{30}}$
BETA
