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If the tangent to the curve $y = \frac{x}{x^2 - 3}$, $x \in \mathbb{R}$, $(x \neq \pm\sqrt{3})$, at a point $(\alpha, \beta) \neq (0, 0)$ on it is parallel to the line $2x + 6y - 11 = 0$, then:
(1) $|6\alpha + 2\beta| = 19$
(2) $|6\alpha + 2\beta| = 9$
(3) $|2\alpha + 6\beta| = 19$
(4) $|2\alpha + 6\beta| = 11$
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