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Let $S = {\theta \in [-2\pi, 2\pi] : 2\cos^2 \theta + 3 \sin \theta = 0}$. Then the sum of the elements of $S$ is:
(1) $\frac{13\pi}{6}$
(2) $\frac{5\pi}{3}$
(3) $2\pi$
(4) $\pi$
$\sin\theta = -\frac{1}{2}$
Sum of all solutions in $[-2\pi, 2\pi]$ is $2\pi$.
BETA
