JEE PYQ: Trigonometric Equations And Inequations Question 13
Question 13 - 2019 (12 Apr Shift 1)
The equation $y = \sin x \sin(x + 2) - \sin^2(x + 1)$ represents a straight line lying in:
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(1) second and third quadrants only
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(2) first, second and fourth quadrants
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(3) first, third and fourth quadrants
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(4) third and fourth quadrants only
Show Answer
Answer:
Solution
$y = \frac{\cos 2 - 1}{2} = -\sin^2 1$
By the graph $y$ lies in III and IV quadrant.
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