JEE PYQ: Trigonometric Equations And Inequations Question 15
Question 15 - 2019 (12 Apr Shift 2)
Let $S$ be the set of all $\alpha \in \mathbb{R}$ such that the equation, $\cos 2x + \alpha \sin x = 2\alpha - 7$ has a solution. Then $S$ is equal to:
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(1) $\mathbb{R}$
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(2) $[1, 4]$
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(3) $[3, 7]$
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(4) $[2, 6]$
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Answer:
Solution
$\sin x = \frac{\alpha - 4}{4} \in [-1, 1] \Rightarrow \alpha \in [2, 6]$
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