JEE PYQ: Trigonometric Equations And Inequations Question 3
Question 3 - 2021 (18 Mar Shift 1)
The number of solutions of the equation $|\cot x| = \cot x + \frac{1}{\sin x}$ in the interval $[0, 2\pi]$ is:
Show Answer
Answer: 1
Solution
If $\cot x > 0 \Rightarrow \frac{1}{\sin x} = 0$ (Not possible)
If $\cot x < 0 \Rightarrow 2\cot x + \frac{1}{\sin x} = 0 \Rightarrow 2\cos x = -1 \Rightarrow x = \frac{2\pi}{3}$ or $\frac{4\pi}{3}$ (reject)
Number of solutions $= 1$
BETA
