JEE PYQ: Vector 3D Question 20
Question 20 - 2021 (25 Feb Shift 1)
The equation of the line through the point $(0, 1, 2)$ and perpendicular to the line $\frac{x - 1}{2} = \frac{y + 1}{3} = \frac{z - 1}{-2}$ is:
(1) $\frac{x}{3} = \frac{y - 1}{-4} = \frac{z - 2}{3}$
(2) $\frac{x}{3} = \frac{y - 1}{4} = \frac{z - 2}{3}$
(3) $\frac{x}{3} = \frac{y - 1}{-4} = \frac{z - 2}{3}$
(4) $\frac{x}{3} = \frac{y - 1}{4} = \frac{z - 2}{-3}$