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Let $L$ be a line obtained from the intersection of two planes $x + 2y + z = 6$ and $y + 2z = 4$. If point $P(\alpha, \beta, \gamma)$ is the foot of perpendicular from $(3, 2, 1)$ on $L$, then the value of $21(\alpha + \beta + \gamma)$ equals:
(1) $142$
(2) $68$
(3) $136$
(4) $102$
BETA
