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The distance of the point $(1, -2, 3)$ from the plane $x - y + z = 5$ measured parallel to the line $\frac{x}{2} = \frac{y}{3} = \frac{z}{-6}$ is:
(1) $\frac{7}{5}$
(2) $1$
(3) $\frac{1}{7}$
(4) $7$
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