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The shortest distance between the lines $\frac{x - 3}{3} = \frac{y - 8}{-1} = \frac{z - 3}{1}$ and $\frac{x + 3}{-3} = \frac{y + 7}{2} = \frac{z - 6}{4}$ is:
(1) $2\sqrt{30}$
(2) $\frac{7}{2}\sqrt{30}$
(3) $3\sqrt{30}$
(4) $3$
BETA
