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If the foot of the perpendicular from point $(4, 3, 8)$ on the line $L_1: \frac{x - a}{l} = \frac{y - 2}{3} = \frac{z - b}{4}$, $l \neq 0$ is $(3, 5, 7)$, then the shortest distance between the line $L_1$ and line $L_2: \frac{x - 2}{3} = \frac{y - 4}{4} = \frac{z - 5}{5}$ is equal to:
(1) $\frac{1}{2}$
(2) $\frac{1}{\sqrt{6}}$
(3) $\sqrt{\frac{2}{3}}$
(4) $\frac{1}{\sqrt{3}}$
BETA
