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Let $P$ be the plane, which contains the line of intersection of the planes, $x + y + z - 6 = 0$ and $2x + 3y + z + 5 = 0$ and it is perpendicular to the $xy$-plane. Then the distance of the point $(0, 0, 256)$ from $P$ is equal to:
(1) $17/\sqrt{5}$
(2) $63\sqrt{5}$
(3) $205\sqrt{5}$
(4) $11/\sqrt{5}$
BETA
