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If $Q(0, -1, -3)$ is the image of the point $P$ in the plane $3x - y + 4z = 2$ and $R$ is the point $(3, -1, -2)$, then the area (in sq. units) of $\triangle PQR$ is:
(1) $2\sqrt{13}$
(2) $\frac{\sqrt{91}}{4}$
(3) $\frac{\sqrt{91}}{2}$
(4) $\frac{\sqrt{65}}{2}$
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