JEE PYQ: Vector 3D Question 57
Question 57 - 2019 (10 Apr Shift 2)
A perpendicular is drawn from a point on the line $\frac{x - 1}{2} = \frac{y + 1}{-1} = \frac{z}{1}$ to the plane $x + y + z = 3$ such that the foot of the perpendicular $Q$ also lies on the plane $x - y + z = 3$. Then the co-ordinates of $Q$ are:
(1) $(1, 0, 2)$
(2) $(2, 0, 1)$
(3) $(-1, 0, 4)$
(4) $(4, 0, -1)$