JEE PYQ: Vector 3D Question 61
Question 61 - 2019 (09 Jan Shift 1)
The equation of the line passing through $(-4, 3, 1)$, parallel to the plane $x + 2y - z - 5 = 0$ and intersecting the line $\frac{x + 1}{-3} = \frac{y - 3}{2} = \frac{z - 2}{-1}$ is:
(1) $\frac{x - 4}{2} = \frac{y + 3}{1} = \frac{z + 1}{4}$
(2) $\frac{x + 4}{1} = \frac{y - 3}{-1} = \frac{z - 1}{3}$
(3) $\frac{x + 4}{3} = \frac{y - 3}{-1} = \frac{z - 1}{1}$
(4) $\frac{x + 4}{-1} = \frac{y - 3}{1} = \frac{z - 1}{1}$
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