JEE PYQ: Vector 3D Question 67
Question 67 - 2019 (10 Jan Shift 2)
On which of the following lines lies the point of intersection of the line, $\frac{x - 4}{2} = \frac{y - 5}{2} = \frac{z - 3}{1}$ and the plane, $x + y + z = 2$?
(1) $\frac{x + 3}{3} = \frac{4 - y}{3} = \frac{z + 1}{-2}$
(2) $\frac{x - 4}{1} = \frac{y - 5}{1} = \frac{z - 5}{-1}$
(3) $\frac{x - 1}{1} = \frac{y - 3}{2} = \frac{z + 4}{-5}$
(4) $\frac{x - 2}{2} = \frac{y - 3}{2} = \frac{z + 3}{2}$