JEE PYQ: Vector 3D Question 72
Question 72 - 2019 (12 Jan Shift 1)
If an angle between the line, $\frac{x + 1}{2} = \frac{y - 2}{1} = \frac{z - 3}{-2}$ and the plane, $x - 2y - kx = 3$ is $\cos^{-1}\left(\frac{2\sqrt{2}}{3}\right)$, then a value of $k$ is:
(1) $\sqrt{\frac{5}{3}}$
(2) $\sqrt{\frac{3}{5}}$
(3) $-\frac{3}{5}$
(4) $-\frac{3}{5}$