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JEE PYQ: Vector 3D Question 75

Question 75 - 2019 (12 Jan Shift 2)

The perpendicular distance from the origin to the plane containing the two lines, $\frac{x + 2}{3} = \frac{y - 2}{5} = \frac{z + 5}{7}$ and $\frac{x - 1}{1} = \frac{y - 4}{4} = \frac{z + 4}{7}$, is:

(1) $11\sqrt{6}$

(2) $\frac{11}{\sqrt{6}}$

(3) $11$

(4) $6\sqrt{11}$

Show Answer

Answer: (2)


Learning Progress: Step 75 of 75 in this series