JEE PYQ: Alternating Current Question 12
Question 12 - 2021 (24 Feb Shift 2)
A series LCR circuit is designed to resonate at an angular frequency $\omega_0 = 10^5$ rad/s. The circuit draws 16 W power from 120 V source at resonance. The value of resistance ‘$R$’ in the circuit is ____ $\Omega$.
Show Answer
Answer: 900
Solution
$P = \frac{V^2}{R}$. $16 = \frac{120^2}{R} \Rightarrow R = \frac{14400}{16} = 900\Omega$.