JEE PYQ: Alternating Current Question 16
Question 16 - 2021 (25 Feb Shift 2)
An LCR circuit contains resistance of $110\Omega$ and a supply of 220 V at 300 rad/s angular frequency. If only capacitance is removed from the circuit, current lags behind the voltage by $45°$. If on the other hand, only inductor is removed the current leads by $45°$ with the applied voltage. The rms current flowing in the circuit will be:
(a) 2.5 A (b) 2 A (c) 1 A (d) 1.5 A
Show Answer
Answer: (b)
Solution
Since $\phi$ remains same, circuit is in resonance. $I_{rms} = \frac{V_{rms}}{R} = \frac{220}{110} = 2$ A.
BETA
