JEE PYQ: Alternating Current Question 19
Question 19 - 2021 (26 Feb Shift 2)
Find the peak current and resonant frequency of the following circuit. [$V = 30 \sin 10^5 t$, $L = 100$ mH, $C = 100\mu$F, $R = 120\Omega$]
(a) 0.2 A and 100 Hz (b) 2 A and 50 Hz (c) 2 A and 100 Hz (d) 0.2 A and 50 Hz
Show Answer
Answer: (d)
Solution
$X_L = 10$, $X_C = 100$. $i = \frac{30}{\sqrt{90^2 + 120^2}} = \frac{30}{150} = 0.2$ A. Resonance frequency $\approx 50$ Hz.
BETA
