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An AC circuit has $R = 100,\Omega$, $C = 2,\mu$F and $L = 80$ mH, connected in series. The quality factor of the circuit is:
(a) 2 (b) 0.5 (c) 20 (d) 400
$Q = \frac{1}{R}\sqrt{\frac{L}{C}} = \frac{1}{100}\sqrt{\frac{80 \times 10^{-3}}{2 \times 10^{-6}}} = \frac{200}{100} = 2$.
BETA
