JEE PYQ: Alternating Current Question 28
Question 28 - 2020 (07 Jan Shift 2)
An emf of 20 V is applied at time $t = 0$ to a circuit containing in series 10 mH inductor and $5,\Omega$ resistor. The ratio of the currents at time $t = \infty$ and at $t = 40$ s is close to: (Take $e^2 = 7.389$)
(a) 1.06 (b) 1.15 (c) 1.46 (d) 0.84
Show Answer
Answer: (a)
Solution
$I_\infty = 4$ A. $I_{40} = 4(1 - e^{-20000})$. Ratio $\approx 1.06$.