JEE PYQ: Alternating Current Question 29
Question 29 - 2020 (08 Jan Shift 2)
As shown in the figure, a battery of emf $\epsilon$ is connected to an inductor $L$ and resistance $R$ in series. The switch is closed at $t = 0$. The total charge that flows from the battery, between $t = 0$ and $t = t_c$ ($t_c$ is the time constant of the circuit) is:
(a) $\frac{\epsilon}{eL}$ (b) $\frac{\epsilon L}{R^2}\left(1 - \frac{1}{e}\right)$ (c) $\frac{\epsilon L}{R^2}$ (d) $\frac{\epsilon R}{eL^2}$
Show Answer
Answer: (a)
Solution
$q = \int_0^{\tau_c} i,dt = \frac{\epsilon L}{R^2 e}$.
BETA
