JEE PYQ: Alternating Current Question 30
Question 30 - 2020 (09 Jan Shift 2)
In LC circuit the inductance $L = 40$ mH and capacitance $C = 100,\mu$F. If a voltage $V(t) = 10\sin(314,t)$ is applied to the circuit, the current in the circuit is given as:
(a) 0.52 cos 314 t (b) 10 cos 314 t (c) 5.2 cos 314 t (d) 0.52 sin 314 t
Show Answer
Answer: (a)
Solution
$Z = X_C - X_L = 19.28\Omega$. Current $= \frac{10}{19.28}\cos(314t) = 0.52\cos(314t)$.
BETA
