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An alternating voltage $v(t) = 220\sin 100\pi t$ volt is applied to a purely resistive load of $50\Omega$. The time taken for the current to rise from half of the peak value to the peak value is:
(a) 5 ms (b) 2.2 ms (c) 7.2 ms (d) 3.3 ms
$\Delta t = \frac{1}{200} - \frac{1}{600} = \frac{2}{600} = 3.3$ ms.
BETA
