JEE PYQ: Alternating Current Question 36
Question 36 - 2019 (09 Jan Shift 2)
A series AC circuit containing an inductor (20 mH), a capacitor (120 $\mu$F) and a resistor (60 $\Omega$) is driven by an AC source of 24 V/50 Hz. The energy dissipated in the circuit in 60 s is:
(a) $5.65 \times 10^2$ J (b) $2.26 \times 10^3$ J (c) $5.17 \times 10^2$ J (d) $3.39 \times 10^3$ J
Show Answer
Answer: (c)
Solution
$Z = 20\sqrt{10}\Omega$. $P_{avg} = 8.64$ W. Energy $= 8.64 \times 60 = 5.17 \times 10^2$ J.
BETA
