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The wavelength of the photon emitted by a hydrogen atom when an electron makes a transition from $n = 2$ to $n = 1$ state is:
(1) 194.8 nm
(2) 490.7 nm
(3) 913.3 nm
(4) 121.8 nm
$\frac{1}{\lambda} = R\left(\frac{1}{1^2} - \frac{1}{2^2}\right) = \frac{3R}{4}$. $\Delta E = 10.2$ eV. $\lambda = \frac{12375}{10.2} \approx 121.8$ nm.
BETA
