JEE PYQ: Atomic Physics Question 20
Question 20 - 2021 (25 Feb Shift 2)
An electron of mass $m_e$ and a proton of mass $m_p = 1836, m_e$, are moving with the same speed. The ratio of their de Broglie wavelength $\frac{\lambda_e}{\lambda_p}$ will be:
(1) 918
(2) 1836
(3) $\frac{1}{1836}$
(4) 1
Show Answer
Answer: (2)
Solution
Given mass of electron $= m_e$. Mass of proton $= m_p$, given $m_p = 1836, m_e$. From de-Broglie wavelength $\lambda = \frac{h}{p} = \frac{h}{mv}$. $\frac{\lambda_e}{\lambda_p} = \frac{m_p}{m_e} = 1836$.
BETA
