JEE PYQ: Atomic Physics Question 32
Question 32 - 2020 (04 Sep Shift 2)
In a photoelectric effect experiment, the graph of stopping potential $V$ versus reciprocal of wavelength obtained is shown in the figure. As the intensity of incident radiation is increased:
(1) Straight line shifts to right
(2) Slope of the straight line gets more steep
(3) Straight line shifts to left
(4) Graph does not change
Show Answer
Answer: (4)
Solution
According to Einstein’s photoelectric equation $eV_s = \frac{hc}{\lambda} - \phi_0$. Comparing with $y = mx + c$: slope $= \frac{hc}{e}$. Increasing the frequency of incident radiation has no effect on work function and frequency. So, graph will not change.
BETA
