JEE PYQ: Atomic Physics Question 46
Question 46 - 2020 (09 Jan Shift 2)
The energy required to ionise a hydrogen like ion in its ground state is 9 Rydbergs. What is the wavelength of the radiation emitted when the electron in this ion jumps from the second excited state to the ground state?
(1) 24.2 nm
(2) 11.4 nm
(3) 35.8 nm
(4) 8.6 nm
Show Answer
Answer: (2)
Solution
According to Bohr’s Theory, $Z = 3$. $\frac{1}{\lambda} = 9R\left(1 - \frac{1}{9}\right) = 8R$. $\lambda = \frac{1}{8R} = \frac{1}{8 \times 10973731.6}$ m$^{-1}$. $\lambda = 11.39$ nm.
BETA
