JEE PYQ: Capacitance Question 13
Question 13 - 2020 (02 Sep Shift 2)
A 10 $\mu$F capacitor is fully charged to a potential difference of 50 V. After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V. The capacitance of the second capacitor is:
(1) 15 $\mu$F
(2) 30 $\mu$F
(3) 20 $\mu$F
(4) 10 $\mu$F
Show Answer
Answer: (1)
Solution
Common potential $V = \frac{C_1 V_1 + C_2 V_2}{C_1 + C_2}$. $20 = \frac{10 \times 50 + 0}{10 + C}$. $C = 15,\mu$F.
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