JEE PYQ: Capacitance Question 14
Question 14 - 2020 (03 Sep Shift 1)
In the circuit shown in the figure, the total charge is 750 $\mu$C and the voltage across capacitor $C_2$ is 20 V. Then the charge on capacitor $C_2$ is:
($C_1 = 15,\mu$F, $C_3 = 8,\mu$F, $C_2$ and $C_3$ in parallel)
(1) 450 $\mu$C
(2) 590 $\mu$C
(3) 160 $\mu$C
(4) 650 $\mu$C
Show Answer
Answer: (2)
Solution
Capacitors $C_2$ and $C_3$ are in parallel hence, voltage across $C_2$ = voltage across $C_3 = 20$ V. Charge on capacitor $C_3$: $q_3 = C_3 \times V_3 = 8 \times 20 = 160\mu$C. $q_2 = 750\mu$C $- 160\mu$C $= 590\mu$C.
BETA
