JEE PYQ: Capacitance Question 17
Question 17 - 2020 (05 Sep Shift 2)
In the circuit shown, charge on the 5 $\mu$F capacitor is:
(Circuit: 2 $\mu$F and 4 $\mu$F in parallel across the top, 5 $\mu$F in middle, connected between 6 V sources)
(1) 18.00 $\mu$C
(2) 10.90 $\mu$C
(3) 16.36 $\mu$C
(4) 5.45 $\mu$C
Show Answer
Answer: (1)
Solution
Let $q_1$ and $q_2$ be the charge on capacitors of 2$\mu$F and 4$\mu$F. Charge on capacitor of 5$\mu$F: $Q = q_1 + q_2$. $5V_0 = 2(6 - V_0) + 4(6 - V_0)$. $11V_0 = 36$, $V_0 = \frac{36}{11}$. $Q = 5V_0 = \frac{180}{11}\mu$C $\approx 16.36\mu$C. (Answer key says (1) but calculation gives 16.36.)
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