JEE PYQ: Capacitance Question 2
Question 2 - 2021 (16 Mar Shift 2)
In a parallel plate capacitor set up, the plate area of capacitor is 2 m$^2$ and the plates are separated by 1 m. If the space between the plates are filled with a dielectric material of thickness 0.5 m and area 2 m$^2$ (see fig.) the capacitance of the set-up will be ____$\epsilon_0$.
(Dielectric constant of the material = 3.2)
(Round off to the Nearest Integer)
Show Answer
Answer: 3
Solution
$C = \frac{\epsilon_0 A}{\frac{d}{2K} + \frac{d}{2}} = \frac{2\epsilon_0 A}{\frac{d}{K} + d} = \frac{2 \times 2\epsilon_0}{\frac{1}{3.2} + 1} = \frac{4 \times 3.2}{4.2}\epsilon_0 = 3.04\epsilon_0 \approx 3\epsilon_0$.
BETA
