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In the given circuit, the charge on 4 $\mu$F capacitor will be:
(Circuit: 4 $\mu$F, 5 $\mu$F and 3 $\mu$F capacitors with 1 $\mu$F, connected to 10 V)
(1) 5.4 $\mu$C
(2) 9.6 $\mu$C
(3) 13.4 $\mu$C
(4) 24 $\mu$C
$V_1 + V_2 = 10$. And $4V_1 = 6V_2$. Solving: $V_1 = 6$ V. Charge on 4 $\mu$F: $q = CV_1 = 4 \times 6 = 24,\mu$C.
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