JEE PYQ: Communication System Question 11
Question 11 - 2021 (24 Feb 2021 Shift 1)
An audio signal $v_m = 20 \sin 2\pi(1500t)$ amplitude modulates a carrier $v_c = 80 \sin 2\pi(100,000t)$. The value of percent modulation is
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Answer: 25
Solution
$A_m = 20$, $A_c = 80$. Percentage modulation index $= \frac{A_m}{A_c} \times 100 = \frac{20}{80} \times 100 = 25$.