JEE PYQ: Communication System Question 23
Question 23 - 2019 (09 Apr 2019 Shift 1)
A signal $A\cos\omega t$ is transmitted using $v_0 \sin \omega_0$ modulated (AM) signal is:
(1) $v_0 \sin\omega_0 t + \frac{A}{2} \sin(\omega_0 - \omega)t + \frac{A}{2}(\omega_0 + \omega)t$
(2) $v_0 \sin[\omega_0(1 + 0.01 A \sin\omega t)t]$
(3) $v_0 \sin\omega_0 t + A\cos\omega t$
(4) $(v_0 + A) \cos\omega t \sin\omega_0 t$
Show Answer
Answer: (1)
Solution
AM wave: $m = (v_0 + A \cos\omega t) \sin\omega_0 t = v_0 \sin\omega_0 t + \frac{A}{2}[\sin(\omega_0 - \omega)t + \sin(\omega_0 + \omega)t]$.
BETA
