JEE PYQ: Current Electricity Question 25
Question 25 - 2020 (05 Sep 2020 Shift 2)
In the circuit, given in the figure currents in different branches and value of one resistor are shown. Then potential at point B with respect to the point A is:
(1) +2 V
(2) $-2$ V
(3) $-1$ V
(4) +1 V
Show Answer
Answer: (4)
Solution
Using KCL at junction C: $i_1 + i_5 = i_2$, $1 + i_5 = 2 \Rightarrow i_5 = 1$ A. Using KVL along ACDB: $V_A + 1 + i_5(1)(2) - 2 = V_B$. $V_B - V_A = 3 - 2 = 1$ V.
BETA
