JEE PYQ: Current Electricity Question 3
Question 3 - 2021 (16 Mar 2021 Shift 2)
A resistor develops 500 J of thermal energy in 20 s when a current of 1.5 A is passed through it. If the current is increased from 1.5 A to 3 A, what will be the energy developed in 20 s.
(1) 1500 J
(2) 1000 J
(3) 500 J
(4) 2000 J
Show Answer
Answer: (4)
Solution
$500 = (1.5)^2 \times R \times 20$. When current is 3 A: $E = (3)^2 \times R \times 20 = 4 \times 500 = 2000$ J.
BETA
