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In the given circuit diagram, a wire is joining points B and D. The current in this wire is:
(1) 0.4 A
(2) 2 A
(3) 4 A
(4) zero
From circuit: $R_1 = \frac{4}{5}$, $R_2 = \frac{6}{5}$. $R_{\text{eff}} = 2,\Omega$. $i = \frac{20}{2} = 10$ A. $I_{BC} = \frac{4i}{5} - \frac{3i}{5} = \frac{i}{5} = 2$ A.
BETA
