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JEE PYQ: Current Electricity Question 5

Question 5 - 2021 (17 Mar 2021 Shift 1)

A current of 10 A exists in a wire of cross-sectional area of $5,\text{mm}^2$ with a drift velocity of $2 \times 10^{-3},\text{ms}^{-1}$. The number of free electrons in each cubic meter of the wire is

(1) $2 \times 10^{6}$

(2) $625 \times 10^{25}$

(3) $2 \times 10^{25}$

(4) $1 \times 10^{23}$

Show Answer

Answer: (2)

Solution

$i = neAv_d$. $10 = n \times 1.6 \times 10^{-19} \times 5 \times 10^{-6} \times 2 \times 10^{-3}$. $n = 0.625 \times 10^{28} = 625 \times 10^{25}$.


Learning Progress: Step 5 of 76 in this series