JEE PYQ: Current Electricity Question 52
Question 52 - 2019 (12 Apr 2019 Shift 1)
To verify Ohm’s law, a student connects the voltmeter across the battery as, shown in the figure. The measured voltage is plotted as a function of the current, and the following graph is obtained:
If $V_0$ is almost zero, identify the correct statement:
(1) The emf of the battery is 1.5 V and its internal resistance is $1.5,\Omega$
(2) The value of the resistance R is $1.5,\Omega$
(3) The potential difference across the battery is 1.5 V when it sends a current of 1000 mA
(4) The emf of the battery is 1.5 V and the value of R is $1.5,\Omega$
Show Answer
Answer: (1)
Solution
When $i = 0$, $V = \varepsilon = 1.5$ V. When $i = 1000$ mA, $V \approx 0$. So $\varepsilon = ir$, $1.5 = 1 \times r$, $r = 1.5,\Omega$.
BETA
