JEE PYQ: Current Electricity Question 60
Question 60 - 2019 (10 Jan 2019 Shift 1)
A 2 W carbon resistor is color coded with green, black, red and brown respectively. The maximum current which can be passed through this resistor is:
(1) 20 mA
(2) 100 mA
(3) 0.4 mA
(4) 63 mA
Show Answer
Answer: (1)
Solution
Green(5), Black(0), Red($10^2$), Brown($\pm 1%$). $R = 50 \times 10^2 = 5000,\Omega = 5,\text{k}\Omega$. $P = i^2 R$, $i = \sqrt{\frac{P}{R}} = \sqrt{\frac{2}{5000}} = 20$ mA.
BETA
