JEE PYQ: Current Electricity Question 67
Question 67 - 2019 (11 Jan 2019 Shift 1)
Two equal resistances when connected in series to a battery, consume electric power of 60 W. If these resistances are now connected in parallel combination to the same battery, the electric power consumed will be:
(1) 60 W
(2) 240 W
(3) 120 W
(4) 30 W
Show Answer
Answer: (2)
Solution
In series: $R_{\text{eq}} = 2R$, $P = \frac{\varepsilon^2}{2R} = 60$ W. In parallel: $R_{\text{eq}} = R/2$. $P’ = \frac{\varepsilon^2}{R/2} = \frac{2\varepsilon^2}{R} = 4 \times 60 = 240$ W.
BETA
